Greenrune113 Greenrune113
  • 17-05-2018
  • Mathematics
contestada

QF Q2.) Solve the triangle

QF Q2 Solve the triangle class=

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EEPJR
EEPJR EEPJR
  • 17-05-2018
60°
11
12

see photo for soln
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Asdfjkadfjkakjf Asdfjkadfjkakjf
  • 19-05-2018
C=180-A-B=180-67-53=60deg.

by sine rule

b/sinB=a/sinA
b=a/sinA*sinB
=13/sin(67)*sin(53)
= 11.28

c/sinC=a/sinA
c=a/sinA*sinC
=13/sin(67)*sin(60)
= 12.23

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