The component of the force along the y-axis is given by
[tex]F_y = F \sin \theta[/tex]
where
F is the magnitude of the force
[tex]\theta[/tex] is the angle between the direction of the force and the horizontal (x-axis)
In our problem, F=38 N and [tex]\theta=65^{\circ}[/tex], therefore the y-component of the force is
[tex]F_y = F \sin \theta=(38 N)(\sin 65^{\circ})=34.4 N[/tex]
Therefore, the correct answer is C).
