Tete5417 Tete5417

20-08-2018
Mathematics

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The distance between the points (6, b0 and (2, -4) is 4 to the sqaure root of five. find the value of b

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lesliekolleroxrkcf lesliekolleroxrkcf

20-08-2018

√(6-2)² + (b+4)² = 4√5

√16+b²+8b+16 =√80

b²+8b+32=80

b² + 8b - 48 = 0

(b+12)(b-4)=0

b can be-12 or 4

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