cardinalswimmer1 cardinalswimmer1
  • 18-10-2018
  • Chemistry
contestada

how many chloride ions are in 1.5 moles of aluminum chloride?

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snugglebug1980 snugglebug1980
  • 18-10-2018

AlCl3 = Al3+ + 3Cl- = 4 ions

1 mol AlCl3 = Al3+ + 3Cl- = 4 x 6.023 x 10^23 ions

Hence, 1.5 moles of Aluminum Chloride, AlCl3 = 1.5 x 4 x 6.023 x 10^23 ​ions = 36.14 x 1023 ​ions

Therefore, 36.14 x 10^23 ​ions are there in 1.5 moles of Aluminum Chloride, AlCl3

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