Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10).

A y-10= -1/6(x-2)
b. x-10= 6(y -2)
c. y-2= -1/6(x-10)
d. y-10= 6(x-2)

Question

18-01-2019
Mathematics

contestada

Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10).

A y-10= -1/6(x-2)
b. x-10= 6(y -2)
c. y-2= -1/6(x-10)
d. y-10= 6(x-2)

Respuesta :

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kudzordzifrancis kudzordzifrancis · Answer 1 · 2019-01-18T16:04:35+01:00

ANSWER

A.

[tex]y - 10 = - \frac{1}{6} (x - 2)[/tex]

EXPLANATION

The given line is

[tex]y = 6x - 5[/tex]

The slope of this line is
[tex]6[/tex]

The slope of the line perpendicular to it is

[tex] - \frac{1}{6} [/tex]

The reason is that, the two slopes are negative reciprocal of each other.

The given line passes through,

[tex](2,10)[/tex]

We use the formula,

[tex]y - y_1 = m (x - x_1)[/tex]

where m is the slope.

We substitute the values to get the equation of the required line to be

[tex]y - 10 = - \frac{1}{6} (x - 2)[/tex]

The correct answer is A.

Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10). A y-10= -1/6(x-2) b. x-10= 6(y -2) c. y-2= -1/6(x-10) d. y-10= 6(x-2)

Respuesta :

Otras preguntas

Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10).

A y-10= -1/6(x-2)
b. x-10= 6(y -2)
c. y-2= -1/6(x-10)
d. y-10= 6(x-2)