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17-02-2019
Mathematics

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Please help with 2 questions. Thank you.

Please help with 2 questions Thank you class=

Please help with 2 questions Thank you class=

Respuesta :

17-02-2019

[tex] {e}^{ln(anything)} = anything[/tex]

so here we have:

[tex] {e}^{ln1} = 1[/tex]

[tex] {e}^{ln5x} = 5x[/tex]

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