Answer:
Aziz's money was $30
Osman's money was $15
Step-by-step explanation:
Let
x-----> Aziz's money at first
y-----> Osman's money
we know that
[tex]\frac{x}{y}=\frac{2}{1}[/tex]
[tex]x=2y[/tex] ------> equation A
[tex]\frac{x-10}{y}=\frac{4}{3}[/tex] -----> equation B
substitute equation A in equation B and solve for y
[tex]\frac{2y-10}{y}=\frac{4}{3}\\ \\6y-30=4y\\ \\6y-4y=30\\ \\2y=30\\ \\ y=15[/tex]
Find the value of x
[tex]x=2(15)=30[/tex]
therefore
At first
Aziz's money was $30
Osman's money was $15
