Answer:
145.902 psi
Explanation: Given power = 0.5 hp= 225 ft-lb/sec, N= 300 rpm shaft
dia= 0.5 inch
We know that power transmitted by circular shaft is
[tex]P=\frac{2piNT}{60}[/tex]
now putting the values to find torque
⇒[tex]T=\frac{60P}{2piN}[/tex][tex]=\frac{60\times225}{2\times pi\times300}[/tex]
⇒T=7.16 lb-ft
now to calculate shear stress[tex]\tau=\frac{16T}{pi\timesd^{3} }[/tex]
⇒[tex]\tau =\frac{16\times7.16}{pi\times0.5^3}[/tex]
⇒[tex]\tau[/tex]=145.902 psi
hence maximum shear stress in the shaft is 145.902 psi
