munaaldawoody
munaaldawoody munaaldawoody
  • 19-05-2016
  • Mathematics
contestada

what is the solution to the quadratic equation 8m^2+7m-15=-7 ?

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apologiabiology
apologiabiology apologiabiology
  • 23-05-2016
make equal to zero
add7 both sides
8m^2+7m-8=0
quadratic fomrula

if you have
ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} [/tex]

8m^2+7m-8=0
a=8
b=7
c=-8

x=[tex] \frac{-7+/- \sqrt{7^{2}-4(8)(-8)} }{2(8)} [/tex]
x=[tex] \frac{-7+/- \sqrt{49+256} }{16} [/tex]
x=[tex] \frac{-7+/- \sqrt{305} }{16} [/tex]

x=[tex] \frac{-7+ \sqrt{305} }{16} [/tex] or x=[tex] \frac{-7- \sqrt{305} }{16} [/tex]

aprox
x=-1.52902 or 0.654016


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