MidnightDuel
MidnightDuel MidnightDuel
  • 17-10-2019
  • Chemistry
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maximum mass help please ​

maximum mass help please class=

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mail2bunmi
mail2bunmi mail2bunmi
  • 17-10-2019

Answer:

1449.02g

Explanation:

First confirming that the equations are balance, this shows that the mole ratio of NaCl to Na₂CO₃ is 1 : 1

Therefore, given 800g of NaCl which has 23 + 35.5 = 58.5g/mol

No of Mole required will be 800 / 58.5 = 13.67mol

The mass for Na₂CO₃ that has 23*2 + 12 + 16*3 = 106g/mol to be obtained will be 106 * 13.67 = 1449.02g

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