Answer
given,
v = 26.8 m/s
t = 3.90 s
[tex]a_{avg}=\dfrac{v-u}{t}[/tex]
[tex]a_{avg}=\dfrac{26.8-0}{3.9}[/tex]
[tex]a_{avg}=6.87\ m/s^2[/tex]
average acceleration is equal to [tex]a_{avg}=6.87\ m/s^2[/tex]
v² = u² + 2 a s
[tex]26.8^2= 0^2 + 2\times 9.8 \times s[/tex]
[tex]s = \dfrac{26.8^2}{2\times 9.8}[/tex]
s = 36.64 m
distance travel at that time, s = 36.64 m
