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An archway over a road is cut out of rock. Its shape is modeled by the quadratic funciton: y = 0.1x^2 + 12 for y is greater than or equal to 0.

a) Write an inequality that describes the OPENING of the archway

b) Graph the inequality - I can do this one

c) Can a camper 6ft wide and 7 ft high fir under the arch without crossing the median line? Explain.

Respuesta :

Answer:

Step-by-step explanation:

Given

shape of parabola is [tex]y=0.1x^2+12[/tex]

[tex]y-12=0.1x^2[/tex]

this is parabola which is symmetrical about y axis and vertex at (0,12)

it minimum value can be 12 at x=0

Parabola never intersect with x axis  

(c)Camper is 6 ft wide and 7 ft high

i.e. [tex]x=6 ft[/tex]

[tex]y=0.1(6)^2+12[/tex]

[tex]y=15.6\ ft[/tex]

at [tex]x=6\ ft[/tex] height of arch is [tex]y=15.6\ ft[/tex]

therefore camper will fit under the crossing

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