Answer:
m∠CDB = 90°
m∠CBD = 25°
m∠BCD = 65°
m∠CDA = 90°
m∠CAD = 65°
m∠ACD = 25°
Step-by-step explanation:
All of the triangles are similar:
ΔADC ~ ΔCDB ~ ΔACB
so corresponding angles will be congruent. Of course, the acute angles in a right triangle are complementary, so ∠B = 90° -65° = 25°. Since CD ⊥ AB, both of the angles at D are right angles, 90°.
In the figure, the angles that look like they're the same size are the same size.
