mvnbnicollBrun3shau
mvnbnicollBrun3shau mvnbnicollBrun3shau
  • 20-06-2016
  • Mathematics
contestada

What is the greatest possible integer value of x for which square root of √x-5 is an imaginary number

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Ckaranja
Ckaranja Ckaranja
  • 03-07-2016
The greatest of must be less than five .i.e 4
[tex] \sqrt{4-5} = \sqrt{-1} [/tex]
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Hagrid
Hagrid Hagrid
  • 04-07-2016
The correct answer for this question is 4.

We have to bear in mind that any number  should be less than 5 to make the square root be an imaginary number.
Starting with 4
= square root (4 - 5)
= square root (-1)
= imaginary 

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