Answer:
The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.
Explanation:
power efficiency of electric motor = 70% = 0.70
The power output of the vacuum cleaner =[tex]P_o[/tex]= 200 W
The power output of the vacuum cleaner = [tex]P_i[/tex]
[tex]Efficiency=\frac{P_o}{P_i}[/tex]
[tex]0.70=\frac{200 W}{P_i}[/tex]
[tex]P_i=\frac{200 W}{0.70}=285.71 W[/tex]
The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.
