Answer:
Option 3 → 6.7×10⁵ J
Explanation:
We need to apply the Calorimetry formula to solve this:
Q = m . C . ΔT where:
Q is heat, m is mass, C the specific heat and ΔT → (Final T° - Initial T°)
Let's replace data given:
By density we can determine water's mass.
1 g/mL = water's mass / 2000 mL → water mass = 2000 g
(Note: we convert the volume from L to mL)
Q = 2000 g . 4.18 J/g°C . (100°C - 20°C)
Q = 668800 J ≅ 6.7×10⁵ J
