Seudónimo Seudónimo
  • 19-02-2020
  • Mathematics
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PLEASE HELP!!!!! 30 POINTS!!!

Expand (2x-3y^2)^3 using pascals triangle

Respuesta :

dillonliyanage
dillonliyanage dillonliyanage
  • 19-02-2020

Answer:

[tex](2x-3y^{2} ) * (2x-3y^{2} ) * (2x-3y^{2} )[/tex]

=(1) 2x*2x*2x = 8x^3

(2) -3y^2* -3y^2* -3y^2 = [tex]-27y^{6}[/tex]

(3) 2x * -3y^2 * 2x = -12 x^2 y^2

(4)-3y^2*-3y^2*2x = 18xy^4

(5)  -3y^2*-3y^2*2x = 18xy^4

(6) 3y^2*-3y^2*2x = 18xy^4

(7)  2x * -3y^2 * 2x = -12 x^2 y^2

(8)2x * -3y^2 * 2x = -12 x^2 y^2

final answer: [tex]8x^3 -36x^2y^2+54xy^4-27y^6[/tex]

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