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Write an equation for the nth term of the geometric sequences. Then Find a6


A. 2, 8, 32, 128, ...

B. 0.6, -3, 15, -75, ...

C. -1/8, -1/4, -1/2, -1, ...

D. 0.1, 0.9, 8.1, 72.9, ...

Respuesta :

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Answer: The nth term of a geometric progression is Tn = ar^(n-1)

A. 12

B. 3.6

C. -3/4

D. 0.6

Step-by-step explanation:

The nth term of a geometric progression is Tn = ar^(n-1)

Where Tn= nth term

a = first term

r = common ratio

n = number

A. a6 = (2*6) = 12

B. a6 = (0.6*6) = 3.6

C. a6 = (-1/8*6) = -3/4

D. a6 = (0.1*6) = 0.6

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