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What is the lift (in newtons) due to Bernoulli's principle on a wing of area 96 m2m2 if the air passes over the top and bottom surfaces at speeds of 270 m/sm/s and 150 m/sm/s, respectively?

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Khoso123

Answer:

[tex]F_{lift}=2.42*10^{9} N[/tex]

Explanation:

Apply Bernoulli's principle

[tex]p_{b}+1/2pv_{b}^{2} =p_{t}+1/2pv_{t}^{2} \\p_{b}-p_{t}= 1/2pv_{t}^{2}-1/2pv_{b}^{2}\\p_{b}-p_{t}= 1/2(1.00*10^{3} kgm^{-3} )(270m/s^{2} )-1/2(1.00*10^{3}kgm^{-3} )(150m/s^{2} )\\p_{b}-p_{t}=2.52*10^{7}N/m^{2}\\ F_{lift}=2.52*10^{7}N/m^{2}*96m^{2} \\ F_{lift}=2.42*10^{9} N[/tex]

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