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One-half mole of a monatomic ideal gas expands adiabatically and does 570 J of work. (a) By how many kelvins does its temperature change? (b) Specify whether the change is an increase or a decrease.

Respuesta :

Hashirriaz830

Answer:

-98 K

Explanation:

Given  

[tex]n=1/2=0.5\\W=570 J[/tex]

Given process is adiabatic and hence heat is zero. Thus change in internal energy is given by,  

ΔU=Q-W

    =0-570

    =-570 J

Also for monoatomic gas change in internal energy is,  

ΔU=3/2*n*R*ΔT

ΔT=-98

Since above answer has negative sign , which indicates temperature change is decrease.  

Hence  

The temperature change is approximately -98 K which is decrease.  

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