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At what temperature (in Kelvin) will the diffusion coefficient for the diffusion of species A in metal B have a value of 6.48 × 10-15 m2/s, assuming values of 4.0 × 10-5 m2/s and 230,000 J/mol for D0 and Qd , respectively?

Respuesta :

Olajidey

Answer:

= 1227.9K

Explanation:

Given that,

D₀ = 4.0 x 10⁻⁵ m²/s,

Qd =  230,000 J/mol,

D = 6.48 x 10⁻¹⁵ m²/s

Gas constant R = 8.31 J/mol-K

T = [tex]-\frac{Q_d}{R* (InD - IND_0)}[/tex]

  = [tex]-\frac{230000}{8.31* (In(6.48 * 10^-^1^5) - In(4.0 * 10^-^5)}[/tex]

  = [tex]\frac{-230000}{-187.307}[/tex]

  = 1227.93K

  ≅1227.9K

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