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At a constant temperature, a sample of helium at 760 torr in a closed container was compressed from 5.0 L to 3.0 L. What was the new pressure exerted by the helium on its container?

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Answer:

The new pressure exerted by the He, is 1266.6 Torr

Explanation:

A typical problem of gases where the volume is increased and the moles and T° keeps on constant. This is an indirect proportion because when the volume of the flask is increased, pressue decreases because molecules  collide to a lesser extent with the walls of the vessel.

P₁ . V₁ = P₂ . V₂

760 Torr . 5L = P₂ . 3L

P₂ = (760 Torr . 5L) / 3L

P₂ = 1266.6 Torr

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