Respuesta :

Answer:

+ 0.617 v

Explanation:

Sn2+ (aq) + 2Fe3+ (aq) → 2Fe2+ (aq) + Sn4+ (aq)

half-life

Sn²⁺ → Sn⁴⁺ + 2e⁻    oxidation       E ox = -0.154 v

2 Fe³⁺ + 2e⁻ → 2 Fe ²⁺   reduction  E red = + 0.771 v

E° cell = E°red + E° ox = +0.77 v + (-0.154 v) = + 0.617 v