caitlynball123
caitlynball123 caitlynball123
  • 21-02-2020
  • Mathematics
contestada

In the interval 0 degrees Find the value for x in which sin=0.6691
To the nearest degree

In the interval 0 degrees Find the value for x in which sin06691 To the nearest degree class=

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Poltergeist
Poltergeist Poltergeist
  • 27-02-2020

Answer:

42° and 138°.

Step-by-step explanation:

Here we use the identity that

[tex]sin (x) = sin(180-x )[/tex].

Now, to find [tex]x[/tex], we make use of the inverse sine function:

[tex]x = sin^{-1}(0.0091)[/tex]

[tex]\boxed{ x = 42^o.}[/tex]

Another solution to this is

[tex]x_0= 180 -x= 180-42 \\\\\boxed{ x_0 = 138^o}[/tex]

Thus, the values of [tex]x[/tex] in the interval [tex]0<x<360[/tex] for which [tex]sin(x) =0.6691[/tex] are 42° and 138°.

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