Answer:
[tex]E=\dfrac{Q}{4\pi r^2\varepsilon _0}\\[/tex]
Explanation:
Given that
Charge = Q
Radius of the sphere = R
The distance from center = r
By using Gauss's law ,we can say that
[tex]4\pi r^2\ E=\dfrac{Q}{\varepsilon _0}\\E=\dfrac{Q}{4\pi r^2\varepsilon _0}\\[/tex]
Q=Total charge on the sphere
E=Electric field at distance r
r=Distance from center of the sphere
Therefore the ,magnetic filed outside the sphere is given as
[tex]E=\dfrac{Q}{4\pi r^2\varepsilon _0}\\[/tex]
