tubtubwillrule tubtubwillrule
  • 18-03-2020
  • Mathematics
contestada

Find the center of the circle whose equation is (x-2)^2(y-4)^2=9.
A.(-2,-4)
B.(2,4)
C.(4,2)​

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 18-03-2020

Answer:

B.(2,4)

Step-by-step explanation:

The equation for a circle is written as

(x-h)^2 +(y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-2)^2+(y-4)^2=9.

Rewriting this equation

(x-2)^2+(y-4)^2=3^2

The center is at (2,4)

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