Solution:
Given system of equations are:
-3y + 5x = 26 ------ eqn 1
-2y - 5x = -16 -------- eqn 2
We have to solve the system of equations
Add eqn 1 and eqn 2
-3y + 5x = 26
-2y - 5x = -16
(+) ------------------
-5y = 10
Substitute y = -2 in eqn 1
-3(-2) + 5x = 26
6 + 5x = 26
5x = 26 - 6
5x = 20
Thus solution is x = 4 and y = -2