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A straight wire is positioned in a uniform magnetic field so that the maximum force on it is 4.0 N. If the wire is 80 cm long and carries a current that is 2 A, what is the magnitude of the magnetic field

Respuesta :

ohiekulous

Answer:

B = 2.5 T

Explanation:

F = 4 N

l = 80cm = 0.8 m

I = 2 A

B = ?

at maximum titha = 90degree

F = BILsin(thita)

sin90 = 1

F = BIL

==> B = F/IL

B= 4 ÷ (2×0.8)

B= 4 ÷ 1.6

B= 2.5 T

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