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Customers exiting a bottleneck form a Poisson process with a stationary flow of 400 per hour. What is the expected amount of time needed to observe one customer's (exit) headway that is larger than five times the mean headway

Respuesta :

Answer:

Customer's (exit) = 0.03 minutes per person

Explanation:

Given:

Flow (Ф) = 400 per hour

Times = 5 times headway

Computation:

5 times Poisson Distribution = 400 per hour × 5 time

5 times Poisson Distribution = 2,000 persons

Computation of expected amount of time needed to observe one customer :

Customer's (exit) = 1 hour / 2,000 persons

Customer's (exit) = 60 minutes / 2,000 persons

Customer's (exit) = 0.03 minutes per person

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