Answer:
2.6253 g O2 formed
Explanation:
Given 6.7 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of grams of O2 molecules formed.
x g O2 = 6.7 g KClO3 x [(1 mol KClO3)/ (122.5 g KClO3)] x [(3 mol O2)/ (2 mol KClO3)] x [(32 g O2)/ (1 mol O2)]
x g O2 = 2.6253 g O2 formed
