wolfprocopio wolfprocopio

20-04-2020
Chemistry

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How many moles of gas are present in 1.13 L of gas at 2.09 atm and 291 K?

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MasterTheNoob MasterTheNoob

20-04-2020

Answer:

n = 0.0989 moles

Explanation:

n = PV / RT

P = 2.09atm

V = 1.13L

R = 0.08206

T = 291K

Plug the numbers in the equation.

n = (2.09atm)(1.13L) / (0.08206)(291K)

n = 0.0989 moles

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