Answer:
The concentration is 0.111 M.
Explanation:
Use dimensional analysis to solve the problem. Since both HCl and NaOH are strong, the dissociate completely in solution.
For this neutralization, the reaction is HCl + NaOH = NaCl + HOH
18.5 mL x [tex]\frac{1 L}{1000 mL}[/tex] x [tex]\frac{0.150 moles NaOH}{1 L}[/tex] x [tex]\frac{1 mole HCl}{1 mole NaOH}[/tex] = 0.002775 moles HCl
Molarity = moles/ Liters
Molarity of HCl = 0.002775 moles HCl / 0.025 L = 0.111 M
