Answer:
-1.6 m/s
Step-by-step explanation:
According to the equations of motion, the height in meters (s) after t seconds is:
[tex]s(t) = s_0+v_0t+a\frac{t^2}{2}[/tex]
If the initial position is 10 m and the initial velocity is 10 m/s:
[tex]s(t) = 100+10+a\frac{t^2}{2}[/tex]
When comparing it with the given height equation, it is possible to obtain the acceleration as follows:
[tex]100+10+a\frac{t^2}{2} =100+10t-0.8t^2\\\frac{a}{2}=-0.8\\ a=-1.6\ m/s[/tex]
Acceleration is -1.6 m/s.
