Answer: The temperature of an ideal gas is 360 K
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 2500 kPa = 24.67 atm (1kPa= 0.0098atm)
V = Volume of gas = 3.00 L
n = number of moles = 2.50 mol
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T = temperature = ?
[tex]T=\frac{PV}{nR}[/tex]
[tex]T=\frac{24.67atm\times 3.00L}{0.0821 L atm/K mol\times 2.50mol}=360K[/tex]
Thus the temperature of an ideal gas if 2.50 moles of the gas occupy a 3.00 liter container is 360 K
