stephantuttle5 stephantuttle5

18-06-2020
Mathematics

contestada

how do I solve? 4a^2+4x-15

Respuesta :

ronhagrid310 ronhagrid310

18-06-2020

Answer:

a = 3/2 or a = -5/2

Step-by-step explanation:

4a^2 + 4x - 15 = 0

<=> 4a^2 + 4x + 1 - 16 = 0

<=> (2a + 1)^2 - 4^2 = 0

<=> (2a + 1 - 4)(2a + 1 + 4) = 0

<=> (2a - 3)(2a + 5) = 0

<=> a = 3/2 or a = -5/2

I hope this helps!

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