lamsalgita371
contestada


Five years ago the age of father was twice as old as the age of daughter. The sum of present ages of the father and daughter is 55 years then find their present ages.​

Respuesta :

TheAnimeGirl

Answer:

Daughter = 20 years old

Father = 35 years old

Step-by-step explanation:

Solution,

Five years ago,

Daughter's age = X - 5

Father's age = 2 ( X - 5 ) = 2x - 10

Present age,

Daughter's age = X years

Father's age = 2x - 5 years

According to Question,

X + 2x - 5 = 55

or, 3x - 5 = 55

or, 3x = 55+5

or, 3x = 60

or, X = 60/3

X = 20

The present age of daughter is 20

Again,

present age of father= 2x - 5

= 2* 20 - 5

= 40 - 5

= 35

Hope this helps...

Good luck on your assignment...

Otras preguntas