Answer:
1/3628800
Step-by-step explanation:
This question requires that we calculate
1/number of permutations of 10 cities
= P(n,k) = n!/(n-k)!
We have
n = 10
k = 10
= 10!/(10-10)!
= 10!
number of permutations of 10 cities 10! This Is equal to 3,628,800
From this answer we the probability of doing a random tour of these 10 different cities in alphabetical order.
And this is
= 1/3,628,800
