Jayy101010 Jayy101010

19-09-2020
Mathematics

contestada

Part A: If (2^6)^x = 1, what is the value of x? Explain your answer. (5 points)
Part B: If (5^0)^ x = 1, what are the possible values of x? Explain your answer.

Respuesta :

surjithayer10 surjithayer10

19-09-2020

Answer:

0,1,-1

Step-by-step explanation:

A.

[tex](2^6)^x=1\\(2)^{6x}=1=2^0\\6x=0\\x=\frac{0}{6}=0[/tex]

B

[tex](5^0)^x=1\\5^0=1\\1^x=1\\x=0,1,-1\\1^0=1\\1^1=1\\1^{-1}=\frac{1}{1^1}=\frac{1}{1}=1[/tex]

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