Answer:
See Below.
Step-by-step explanation:
We want to prove that:
[tex]-(x-3)^2+4=-x^2+6x-5[/tex]
So, let’s expand the left side. This gives us:
[tex]=-(x-3)(x-3)+4[/tex]
Distribute:
[tex]=-(x^2-3x-3x+9)+4[/tex]
Simplify:
[tex]=-(x^2-6x+9)+4[/tex]
Distribute:
[tex]=-x^2+6x-9+4[/tex]
Simplify:
[tex]=-x^2+6x-5[/tex]
Hence:
[tex]-(x-3)^2+4\stackrel{\checkmark}{=}-x^2+6x-5[/tex]
