Answer:
∝ = 28.92 rad/s²
Explanation:
Applying third equation of motion to the angular motion, we have:
2∝θ = ωf² - ωi²
where,
∝ = angular acceleration = ?
θ = angular displacement = (27 rev)(2π rad/1 rev) = 169.64 rad/s
ωf = final angular velocity = 99 rad/s
ωi = initial angular velocity = 0 rad/s
Therefore,
(2)∝(169.64 rad) = (99 rad/s)² - (0 rad/s²)
∝ = (9801 rad²/s²)/(38.8 rad)
∝ = 28.92 rad/s²
