Answer:
20.4m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Distance = 53m
Time = 5.2s
Unknown:
Acceleration = ?
Solution:
This is a linear motion and we use the right motion equation;
S = ut + [tex]\frac{1}{2}[/tex]at²
S is the distance
u is the initial velocity
a is the acceleration
t is the time
Insert the parameters and solve;
53 = (0x 5.2) + [tex]\frac{1}{2}[/tex] x a x 5.2
53 = 2.6a
a = [tex]\frac{53}{2.6}[/tex] = 20.4m/s²
