contestada

Approximately what mass of CuSO4*5H20 (250 g mol^-1) is required to prepare 250 mL of 0.10 M copper(ll)
sulfate solution?
A) 4.0 g
B
6.2 g
С
34 g
D
85 g
E
140 g

Respuesta :

ardni313

Mass of CuSO₄.5H₂0 = 6.25 g (B)

Further explanation

MW CuSO₄.5H₂0 =250 g/ mol

mol of CuSO₄

[tex]\tt 0.25\times 0.1=0.025[/tex]

mass of CuSO₄ (MW=159.61 g/mol)

[tex]\tt 0.025\times 159.61=3.99~g[/tex]

[tex]\tt mass~CuSO_4=\dfrac{159.61}{250}\times mass~CuSO_4.5H_2O\\\\mass~CuSO_4.5H_2O=\dfrac{3.99\times 250}{159.61}=6.25~g[/tex]

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