Crystalinq
Crystalinq Crystalinq
  • 19-11-2020
  • Mathematics
contestada

The endpoints of a diameter of a circle are (2,4) and (−4,7).

What is the standard form of the equation of this circle?

Respuesta :

evgeniylevi
evgeniylevi evgeniylevi
  • 06-07-2022

Answer:

(x+1)²+(y-5.5)²=11.25

Step-by-step explanation:

1) the common view is:

(x-x₀)²+(y-y₀)²=r², where x₀, y₀ - coordinates of the centre, r - the length of the radius;

2) the coordinates of the centre can be calculated:

[tex]x_0=\frac{2-4}{2}=-1; \ y_0=\frac{4+7}{2}=5.5.[/tex]

3) the length of the radius is:

[tex]r=\sqrt{(-1-2)^2+(5.5-4)^2}=\sqrt{11.25}.[/tex]

4) if the centre is (-1;5.5) and r²=11.25, then it is possible to make up the required equation:

(x+1)²+(y-5.5)²=11.25

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