Answer:150
Explanation:n =
x = 106
\hat p = x / n = 106 / 150 = 0.707
1 -\hat p = 1 - 0.707 = 0.293
At 99% confidence level the z is ,
\alpha = 1 - 99% = 1 - 0.99 = 0.01
\alpha / 2 = 0.01 / 2 = 0.005
Z\alpha/2 = Z0.005 = 2.576
Margin of error = E = Z\alpha / 2 * \sqrt((\hat p * (1 - \hat p)) / n)
= 2.576 * (\sqrt((0.707 * 0.293) / 150)
=0.096
A 99% confidence interval for population proportion p is ,
\hat p- E < P <\hat p + E
0.707 - 0.096 < p < 0.707 + 0.096
0.611 < p < 0.803
