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16-12-2020
Mathematics

contestada

In \triangle BCD,△BCD, \overline{BC}\cong \overline{DB}
BC
≅
DB
and \text{m}\angle B = 147^{\circ}.m∠B=147
∘
. Find \text{m}\angle D.m∠D.

Respuesta :

Litzy01 Litzy01

02-03-2021

Answer:16.5

Step-by-step explanation: x+x+147=180

2x+147=180

2x=33

2x=33 divide by 2

x=16.5

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