Answer: 1.414 mol Cl-
Explanation:
First, let's find the moles of BeCl2.
1.79 M = 1.79 mol/L
395 mL = 0.395 L , since 1L = 1000 mL
Using stoichiometry,
1.79 mol/L *0.395 L = about 0.707 mol BeCl2
Now, we have 0.707 mol of BeCl2, but we are trying to find moles of Cl-
There are two chloride ions in each molecule of BeCl2, so there will be twice as many moles as well.
0.707 mol BeCl * (2 mol Cl- / 1 mol BeCl) = 1.414 mol Cl-
Hope this helps!
