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A fireman's water hose shoots 320 kg of water each second against the door of a building. The velocity of the water is 20 m/s and the water strikes the door horizontally and doesnt bounce back. What average force is exerted by the stream of water?

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boffeemadrid

Answer:

[tex]6400\ \text{N}[/tex]

Step-by-step explanation:

[tex]\dfrac{m}{t}[/tex] = Mass flow rate of water = 320 kg/s

[tex]m[/tex] = Mass of water on the door

[tex]t[/tex] = Time

[tex]v[/tex] = Velocity of water on the door = 20 m/s

Force is given by

[tex]F=\dfrac{m}{t}v\\\Rightarrow F=320\times 20\\\Rightarrow F=6400\ \text{N}[/tex]

The average force is exerted by the stream of water is [tex]6400\ \text{N}[/tex].

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