Answer:
1/2
Step-by-step explanation:
Given the limit of the function expressed as;
[tex]\lim_{n \to \infty} \frac{3n^4-10}{6n^4+7} \\[/tex]
To take the limit, we nee to divide through by the highest power of n first
[tex]\lim_{n \to \infty} \frac{3n^4/n^4-10/n^2}{6n^4/n^4+7/n^4}\\= \lim_{n \to \infty} \frac{3-10/n^2}{6+7/n^4}\\= \frac{3-10/(\infty)^2}{6+7/(\infty)^4}\\= \frac{3-0}{6-0}\\= \frac{3}{6}\\ = \frac{1}{2}\\[/tex]
Hence the limit of the the nth term as n becomes increasingly large is 1/2
