Answer: The final temperature of the water will be [tex]34.0^0C[/tex]
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed=[tex]6832[/tex] Joules
m= mass of water = [tex]5.9mol\times 18g/mol=106.2g[/tex]
c = specific heat capacity = [tex]4.184J/g^0C[/tex]
Initial temperature of the water = [tex]T_i[/tex] = [tex]18.6^0C[/tex]
Final temperature of the water = [tex]T_f[/tex] = ?
Putting in the values, we get:
[tex]6832=106.2\times 4.184\times (T_f-18.6)[/tex]
[tex]T_f=34.0^0C[/tex]
The final temperature of the water will be [tex]34.0^0C[/tex]
