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An ideal gas that is confined in piston-cylinder assembly (i.e., closed system) goes from an initial state of 1 bar at 300 K to a final state of 3 bar at 300 K by the following two-step process.

Process Path.
(Step 1) Heating at constant volume, and then
( Step 2) Cooling by holding the pressure constant.

Required:
a. Determine the initial and final molar mass.
b. Illustrate the two paths on a pressure-volume diagram. Clearly label the initial and final states, process steps and the direction of each step in the diagram.

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Answer:

Explanation:

From the given information;

Using ideal gas equation:

pV = nRT

when n = 1 mol

[tex]V = \dfrac{RT}{p}[/tex]

Initial molar volume = [tex]\dfrac{8.314 \ L.bar .k^{-1}.mol^{-1} \times 300 \ K}{1 \ bar}[/tex]

Initial molar volume = 2494.2 L.mol⁻¹

Final molar volume = [tex]\dfrac{8.314 \ L.bar .k^{-1}.mol^{-1} \times 300 \ K}{3 \ bar}[/tex]

Final molar volume = 831.4 L.mol⁻¹

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